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प्रश्न
The tangent to a circle of radius 8 cm from an external point P is of length 6 cm. Find the distance of P from the nearest point to the circle.

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उत्तर
Given
Radius of circle = 8 cm.
Length of tangent from point P = 6 cm.
PA is tangent, O is centre, A is point of tangency.
Need to find: the distance of P from the nearest point on the circle.
That nearest point is the point where the line PO meets the circle.
Step 1: Use the tangent–radius right-angle property.
Radius to the point of tangency is perpendicular to the tangent:
OA ⊥ PA
Thus, triangle POA is right-angled at A.
Step 2: Apply Pythagoras
PO2 = PA2 + OA2
PO2 = 62 + 82
PO2 = 36 + 64 = 100
PO = 10 cm
Step 3: Distance from P to the nearest point on the circle.
The nearest point lies on the line PO.
Distance = PO − radius:
Required distance = 10 − 8 = 2 cm
