Advertisements
Advertisements
Question
The table given below contains some measures of the right angled triangle. Find the unknown values.
| Base | Height | Area |
| ? | 12 m | 24 sq.m |
Advertisements
Solution
Area of the right triangle = `1/2 xx ("base" xx "height") "unit"^2`
24 = `1/2 xx "b" xx 12 "m"^2`
Base = `(24 xx 2)/12` m
= 4 m
Base = 4 m
Tabulating the unknown values
| Base | Height | Area |
| 4 m | 12 m | 24 sq.m |
APPEARS IN
RELATED QUESTIONS
Find the area of a triangle with vertices at the point given in the following:
(2, 7), (1, 1), (10, 8)
Prove that the points (a, 0), (0, b) and (1, 1) are collinear if `1/a+1/b=1`
If `a≠ b ≠ c`, prove that the points (a, a2), (b, b2), (c, c2) can never be collinear.
Prove that the points (a, b), (a1, b1) and (a −a1, b −b1) are collinear if ab1 = a1b.
Find the centroid of the triangle whosw vertices is (1,4), (-1,1) and (3,2) .
Two vertices of a triangle are (1, 2), (3, 5) and its centroid is at the origin. Find the coordinates of the third vertex.
prove that the points A (7, 10), B(-2, 5) and C(3, -4) are the vertices of an isosceles right triangle.
Show that the following points are collinear:
A(8,1), B(3, -4) and C(2, -5)
If the points A (x, y), B (3, 6) and C (−3, 4) are collinear, show that x − 3y + 15 = 0.
The table given below contains some measures of the right angled triangle. Find the unknown values.
| Base | Height | Area |
| 20 cm | 40 cm | ? |
