Question

The system of linear equations px + qy = r and p₁x + q₁y = r₁ has a unique solution, if:

Options

• pq ≠ p₁q₁

• pp₁ ≠ qq₁

• pq₁ ≠ qp₁

• pqr ≠ p₁q₁r₁

Answer 1

pq₁ ≠ qp₁

Explanation:

`(a_1)/(a_2) ≠ (b_1)/(b_2)`

⇒ `p/(p_1) ≠ q/(q_1)`

⇒ pq₁ ≠ qp₁