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The sum S of n successive odd numbers starting from 3 is given by the relation: S = n(n + 2). Determine n, if the sum is 168.

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Question

The sum S of n successive odd numbers starting from 3 is given by the relation: S = n(n + 2). Determine n, if the sum is 168.

Sum
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Solution

From the given information, we have:

n(n + 2) = 168

n2 + 2n – 168 = 0

n2 + 14n – 12n – 168 = 0

n(n + 14) – 12(n + 14) = 0

(n + 14)(n – 12) = 0

n = –14, 12

But, n cannot be negative.

Therefore, n = 12.

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Chapter 6: Solving (simple) Problems (Based on Quadratic Equations) - Exercise 6 (D) [Page 78]

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Selina Concise Mathematics [English] Class 10 ICSE
Chapter 6 Solving (simple) Problems (Based on Quadratic Equations)
Exercise 6 (D) | Q 1. | Page 78
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