Question

The sum of three numbers is 58. The second number is three times of two-fifth of the first number and the third number is 6 less than the first number. Find the three numbers

Answer 1

Here what we know

a + b + c = 58  ...(sum of three numbers is 58)

Let the first number be ‘x’

b = a × 3  ...(the second number is three times of the first `2/5` number)

b = `3 xx 2/5x = 6/5x`

Third number = x – 6

Sum of the numbers is given as 58.

∴ `x + 6/5x + (x - 6)` = 58

Multiplying by 5 throughout, we ge

5 × x + 6x + 5 × (x – 6) = 58 × 5

5x + 6x + 5x – 30 = 290

∴ 16x = 290 + 30

∴ 16x = 320

∴ x = `320/16`

x = 20

1^st number = 20

2^nd number = `3 xx 2/5 xx 20 = 6/5 xx 20` = 24

3^rd number = 24 – 16 = 14