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Question
The sum of the length, breadth and height of a cuboid is `5sqrt(3)` cm and length of its diagonal is `3sqrt(5)` cm, then its total surface area is ______.
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Solution
The sum of the length, breadth and height of a cuboid is `5sqrt(3)` cm and length of its diagonal is `3sqrt(5)` cm, then its total surface area is 30 cm2.
Explanation:
Given: `l + b + h = 5sqrt(3)` cm
Diagonal `d = sqrt(l^2 + b^2 + h^2) = 3sqrt(5)` cm
(Use: d2 = l2 + b2 + h2 and Total surface area = 2(lb + bh + lh).)
Step wise calculation:
1. Compute squares:
`(l + b + h)^2 = (5sqrt(3))^2 = 75`
`d^2 = (3sqrt(5))^2 = 45`
So l2 + b2 + h2 = 45.
2. Expand (l + b + h)2:
l2 + b2 + h2 + 2(lb + bh + lh) = 75
3. Substitute l2 + b2 + h2 = 45:
45 + 2(lb + bh + lh) = 75
⇒ 2(lb + bh + lh) = 30
⇒ (lb + bh + lh) = 15
4. Total surface area = 2(lb + bh + lh)
= 2 × 15
= 30 cm2
