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Question
‘The sum of the ages of a boy and his sister (in years) is 25 and product of their ages is 150. Find their present ages.
Sum
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Solution
Let the boy and his sister's ages be ‘x’ years and ‘y’ years, respectively
According to the question,
x + y = 25 ...(i)
and xy = 150
or, y = `150/x` ...(ii)
Using equation (ii) in equation (i), we get
`x + 150/x` = 25
⇒ x2 – 25x + 150 = 0
⇒ x2 – 15x – 10x + 150 = 0
⇒ x(x – 15) – 10(x – 15) = 0
⇒ (x – 15)(x – 10) = 0
⇒ x – 15 = 0 or x – 10 = 0
⇒ x = 15 or x = 10
When x = 15 i.e., boy's age is 15 years.
Then, sister's age, y = `150/15` = 10 years
When x = 10 i.e, boy's age is 10 years
Then, sister's age, y = `150/10` = 15 years
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