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Question
The spin magnetic moment of cobalt in the compound Hg [Co(SCN)4] is:-
Options
`sqrt(3)`
`sqrt(8)`
`sqrt(15)`
`sqrt(24`
MCQ
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Solution
`sqrt(15)`
Explanation:
The O.N of CO in the complex is
| 3d | +2 | 4s | 4d | ||||||
| ↑↓ | ↑↓ | ↑ | ↑ | ↑ | ↑↓ | ||||
| 3d | |||||||||
| ↑↓ | ↑↓ | ↑ | ↑ | ↑ | |||||
No of unpaired electron (n) = 3
Spin magnetic moment (ms) = `sqrt(n(n + 2))`
`sqrt(3(3 + 2)) = sqrt(15)`
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