Question

The specific conductance of `N/50` solution of KCl at 25°C is 0.002765 mho cm⁻¹. If the resistance of a cell containing this solution is 400 ohms, find out the cell constant.

Answer 1

Given: Specific conductance (κ) = 0.002765 S cm⁻¹

Resistance (R) = 400 Ω

We know that 

Cell constant = κ × R

= 0.002765 × 400

= 1.106 cm⁻¹