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प्रश्न
The specific conductance of `N/50` solution of KCl at 25°C is 0.002765 mho cm−1. If the resistance of a cell containing this solution is 400 ohms, find out the cell constant.
संख्यात्मक
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उत्तर
Given: Specific conductance (κ) = 0.002765 S cm−1
Resistance (R) = 400 Ω
We know that
Cell constant = κ × R
= 0.002765 × 400
= 1.106 cm−1
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