Question

The solubility of AgCl_(s) with solubility product 1.6 × 10⁻¹⁰ in 0.1 M NaCl solution would be ____________.

Options

• 1.26 × 10⁻⁵ M

• 1.6 × 10⁻⁹ M

• 1.6 × 10⁻¹¹ M

• Zero

Answer 1

The solubility of AgCl_(s) with solubility product 1.6 × 10⁻¹⁰ in 0.1 M NaCl solution would be 1.6 × 10⁻⁹ M.

Explanation:

\[\ce{AgCl_{(s)} ⇌ Ag^+_{( aq)} + Cl^-_{( aq)}}\]

\[\ce{\underset{0.1 M}{NaCl} -> \underset{0.1 M}{Na^+} + \underset{0.1 M}{Cl^-}}\]

K_sp = 1.6 × 10⁻¹⁰

K_sp = [Ag⁺] [Cl^–]

K_sp = (S) (S + 0.1)

0.1 > > > S

∴ S + 0.1 ≃ 0.1

∴ S = `(1.6 xx 10^-10)/0.1`

= 1.6 × 10⁻⁹