Question

Derive the relationship between solubility and solubility product of AgBr.

Answer 1

Relation between Solubility (S) and Solubility product (K_sp) of AgBr:

\[\ce{AgBr_{(s)} <=> \underset{[s]}{Ag^+}_{(aq)}+ \underset{[S]}{Br^-}_{(aq)}}\]

where S is the solubility.

K_sp [Ag⁺] [Br^-]

∴ K_sp [S] x [S]

∴ K_sp = S²

∴ `S = sqrtk_(sp)`