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प्रश्न
Derive the relationship between solubility and solubility product of AgBr.
थोडक्यात उत्तर
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उत्तर
Relation between Solubility (S) and Solubility product (Ksp) of AgBr:
\[\ce{AgBr_{(s)} <=> \underset{[s]}{Ag^+}_{(aq)}+ \underset{[S]}{Br^-}_{(aq)}}\]
where S is the solubility.
Ksp [Ag+] [Br-]
∴ Ksp [S] x [S]
∴ Ksp = S2
∴ `S = sqrtk_(sp)`
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Solubility Product - Solubility product
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