Advertisements
Advertisements
Question
The smallest number which when diminished by 3 is divisible by 14, 28, 36 and 45, is
Options
1257
1260
1263
none of these
Advertisements
Solution
1263
The smallest number that is exactly divisible by 14, 28, 36, and 45 will be their L.C.M.
So, the required number will be L.C.M. plus 3.

L.C.M. of the three numbers = 22 × 32 × 5 × 7
= 1260
∴ Required number = 1260 + 3 = 1263
APPEARS IN
RELATED QUESTIONS
Test the divisibility of the following numbers by 5:
23590
Test the divisibility of the following numbers by 9:
98712
Test the divisibility of the following numbers by 9:
326999
Test the divisibility of the following number by 11:
83721
In the following number, replace * by the smallest number to make it divisible by 11:
467*91
In the following number, replace * by the smallest number to make it divisible by 11:
9*8071
State if the following is a prime number?
137
State if the following is a prime number?
161
On dividing 5035 by 31, the remainder is 13. Find the quotient.
What least number should be replaced for * so that the number 67301*2 is exactly divisible by 9?
