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The sides of a right-angled triangle containing the right angle are 4x cm and (2x – 1) cm. If the area of the triangle is 30 cm2; calculate the lengths of its sides.

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Question

The sides of a right-angled triangle containing the right angle are 4x cm and (2x – 1) cm. If the area of the triangle is 30 cm2; calculate the lengths of its sides.

Sum
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Solution


Area of triangle = 30 cm2

∴ `1/2 xx (4x) xx (2x - 1) = 30`

`2x^2 - x = 15`

`2x^2 - x - 15 = 0`

`2x^2 - 6x + 5x - 15 = 0`

`2x(x - 3) + 5(x - 3) = 0`

`(x - 3)(2x + 5) = 0`

`x = 3, (-5)/2`

But, x cannot be negative, so x = 3

Thus, we have

AB = 4 × 3 cm = 12 cm

BC = (2 × 3 – 1) cm = 5 cm

CA = `sqrt(12^2 + 5^2)  cm` = 13 cm  ...(Using Pythagoras theorem)

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Chapter 6: Solving (simple) Problems (Based on Quadratic Equations) - Exercise 6 (B) [Page 71]

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Selina Concise Mathematics [English] Class 10 ICSE
Chapter 6 Solving (simple) Problems (Based on Quadratic Equations)
Exercise 6 (B) | Q 1. | Page 71

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