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The resistance of a wire of 0.01 cm radius is 10 Ω. If the resistivity of the wire is 50 × 10-8 Ω, find the length of this wire.

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Question

The resistance of a wire of 0.01 cm radius is 10 Ω. If the resistivity of the wire is 50 × 10-8 Ω, find the length of this wire.

Sum
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Solution

Given, Radius, r = 0.01 cm = 0.0001 m

Resistance, R = 10 Ω

Resistivity, `rho = 50 xx 10^-8` Ω m

R = `rho "L"/"A"`

L = `"RA"/rho`

`= (10 xx 3.14 xx (0.0001)^2)/(50 xx 10^-8)`

= 0.628 m

Hence, the length of the wire is 0.628 m.

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Electrical resistivity of some substances at 20°C
Material Resistivity (Ω m)
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Silver 1.60 × 10−8
Copper 1.62 × 10−8
Aluminium 2.63 × 10−8
Tungsten 5.20 × 10−8
Nickel 6.84 × 10−8
Iron 10.0 × 10−8
Chromium 12.9 × 10−8
Mercury 94.0 × 10−8
Manganese 1.84 × 10−6
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Constantan
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49 × 10−6
Manganin
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44 × 10−6
Nichrome
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100 × 10−6
Insulators Glass 1010 − 1014
Hard rubber 1013 − 1016
Ebonite 1015 − 1017
Diamond 1012 − 1013
Paper (dry) 1012

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