Question

The resistance of 0.01 M NaCl solution in a conductivity cell was found to be 210 Ω. The specific conductance of this solution is 4.5 × 10⁻³ S cm⁻¹. What is the cell constant of the cell?

Answer 1

Given: Resistance (R) = 210 Ω

Specific conductance (κ) = 4.5 × 10⁻³ S cm⁻¹

By using the relation

Cell constant = Specific conductance (κ) × Resistance (R)

= (4.5 × 10⁻³) × 210

= 0.945 cm⁻¹