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प्रश्न
The resistance of 0.01 M NaCl solution in a conductivity cell was found to be 210 Ω. The specific conductance of this solution is 4.5 × 10−3 S cm−1. What is the cell constant of the cell?
संख्यात्मक
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उत्तर
Given: Resistance (R) = 210 Ω
Specific conductance (κ) = 4.5 × 10−3 S cm−1
By using the relation
Cell constant = Specific conductance (κ) × Resistance (R)
= (4.5 × 10−3) × 210
= 0.945 cm−1
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