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The refractive index of the material of glass is 3. If the angle of minimum deviation is equal to the angle of the prism, then the angle of the prism is ______.

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Question

The refractive index of the material of glass is `sqrt3`. If the angle of minimum deviation is equal to the angle of the prism, then the angle of the prism is ______.

`(cos30^circ = sqrt3/2 = sin60^circ, sin30^circ = 1/2 = cos60^circ)`

Options

  • 30°

  • 60°

  • 45°

  • 50°

MCQ
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Solution

The refractive index of the material of glass is `sqrt3`. If the angle of minimum deviation is equal to the angle of the prism, then the angle of the prism is 60°.

Explanation:

Given, μg = `sqrt3`, δm = A

As we know, the refractive index of the prism,

`mu_g = (sin((A + delta_m)/2))/(sin  A/2)`

⇒ `sqrt3 = (sin((A + A)/2))/(sin  A/2)`

= `(sin A)/(sin  A/2) = (2sin  A/2cos  A/2)/(sin  A/2)` (∵ sin2θ = 2sinθ cosθ)

= `2cos  A/2`

⇒ `cos  A/2 = sqrt3/2 = cos30^circ ⇒ A/2 = 30^circ`

or A = 60°

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