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प्रश्न
The refractive index of the material of glass is `sqrt3`. If the angle of minimum deviation is equal to the angle of the prism, then the angle of the prism is ______.
`(cos30^circ = sqrt3/2 = sin60^circ, sin30^circ = 1/2 = cos60^circ)`
पर्याय
30°
60°
45°
50°
MCQ
रिकाम्या जागा भरा
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उत्तर
The refractive index of the material of glass is `sqrt3`. If the angle of minimum deviation is equal to the angle of the prism, then the angle of the prism is 60°.
Explanation:
Given, μg = `sqrt3`, δm = A
As we know, the refractive index of the prism,
`mu_g = (sin((A + delta_m)/2))/(sin A/2)`
⇒ `sqrt3 = (sin((A + A)/2))/(sin A/2)`
= `(sin A)/(sin A/2) = (2sin A/2cos A/2)/(sin A/2)` (∵ sin2θ = 2sinθ cosθ)
= `2cos A/2`
⇒ `cos A/2 = sqrt3/2 = cos30^circ ⇒ A/2 = 30^circ`
or A = 60°
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