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Question
The reactance of the coil is 20 `Omega` and its resistance is 20 `Omega`. It is connected to an A.C. source of e.m.f. 220 V. The peak value of the current in the circuit is ____________.
Options
11 A
`22 sqrt2 "A"`
22 A
`22/sqrt2 "A"`
MCQ
Fill in the Blanks
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Solution
The reactance of the coil is 20 `Omega` and its resistance is 20 `Omega`. It is connected to an A.C. source of e.m.f. 220 V. The peak value of the current in the circuit is 11 A.
Explanation:
`"Z" = sqrt("R"^2 + "X"_"L"^2)`
` = 20 sqrt2 Omega`
`"e"_0 = sqrt2 "e" = 220 sqrt2 "V"`
`therefore "i"_0 = "e"_0/"Z"`
`= (220 sqrt2)/(20sqrt2)`
` = 11 "A"`
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Types of AC Circuits
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