Question

The reactance of the coil is 20 `Omega` and its resistance is 20 `Omega`. It is connected to an A.C. source of e.m.f. 220 V. The peak value of the current in the circuit is ____________.

पर्याय

• 11 A

• `22 sqrt2  "A"`

• 22 A

• `22/sqrt2  "A"`

Answer 1

The reactance of the coil is 20 `Omega` and its resistance is 20 `Omega`. It is connected to an A.C. source of e.m.f. 220 V. The peak value of the current in the circuit is 11 A.

Explanation:

`"Z" = sqrt("R"^2 + "X"_"L"^2)`

` = 20 sqrt2  Omega`

`"e"_0 = sqrt2  "e" = 220 sqrt2  "V"`

`therefore "i"_0 = "e"_0/"Z"`

`= (220 sqrt2)/(20sqrt2)`

` = 11  "A"`