Question

The ratio of prices of two houses was 2 : 3. Two years later when price of first house has increased by 30% and that of the second by ₹  90,000 the ratio of prices becomes 5 : 7. Find the original prices of two houses. 

Answer 1

Ratio of the prices of two houses 2 : 3

Let price of house I be 2x and price of house 2 be 3x. 

After two years, price of house· 1 is increased by 30%

∴ New price of house 1 is 

`"2x" + 30/100 xx "2x"`

2x + 0.6 x = 2.6 x

Price of house 2 is increased by 90,000 

∴ New price of house 2 is 

3x + 90000

The ratio of the new prices of two houses is 5: 7 

`(2.6"x")/(3"x" + 90000) = 5/7`

`therefore 18.2 "x" = 15"x" + 450000`

3.2 x = 450000

x = `450000/3.2`

= 140625

Original price of house 1 is 

2 x = 2 x 1,40,625 = ₹ 2,81,250 

Original price of house 2 is 

3 x = 3 x 1,40,625 = ₹ 4,2l,875