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The ratio of diameter to height of a Borosil cylindrical glass is 3 : 5. If the actual diameter of the glass is 6 cm, then the curved surface area of the glass is ______. - Mathematics

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Question

The ratio of diameter to height of a Borosil cylindrical glass is 3 : 5. If the actual diameter of the glass is 6 cm, then the curved surface area of the glass is ______.

Options

  • 120π

  • 60π

  • 30π

  • 18π

MCQ
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Solution

The ratio of diameter to height of a Borosil cylindrical glass is 3 : 5. If the actual diameter of the glass is 6 cm, then the curved surface area of the glass is 60π.

Explanation:

Given diameter = 6 cm → radius r = 3 cm.

Ratio diameter : height = 3 : 5 

⇒ If diameter = 6 (i.e. 3 × 2) then height = 5 × 2 = 10 cm.

Curved surface area (CSA) of a cylinder = 2πrh

= 2π × 3 × 10

= 60π cm2

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Chapter 23: Competency focused practice questions - COMPETENCY FOCUSED PRACTICE QUESTIONS [Page 522]

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Nootan Mathematics [English] Class 10 ICSE
Chapter 23 Competency focused practice questions
COMPETENCY FOCUSED PRACTICE QUESTIONS | Q 14. | Page 522
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