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Question
The ratio of the intensities at minima to the maxima in the Young's double slit experiment is 9 : 25. Find the ratio of the widths of the two slits.
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Solution
Let w, a,I represent the slit width, amplitude and intensity.
`I_(min)/I_(max)=(a_1-a_2)^2/(a_1+a_2)^2=9/25`
`((a_1-a_2))/((a_1+a_2))=3/5`
Or
`a_1/a_2=4/1`
and
`w_1/w_2=(a_2)^2/(a_2)^2=16/1`
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