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Question
The ratio in which the join of (2, 4) and (10, 12) is divided by the line x = 7 is ______.
Options
3 : 5
5 : 3
1 : 5
3 : 1
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Solution
The ratio in which the join of (2, 4) and (10, 12) is divided by the line x = 7 is 5 : 3.
Explanation:
Any point on the line \[x = 7\], can be defined as \[(7, y).\]
Let point \[(7, y)\] divide line joining \[(2, 4)\] and \[(10, 12)\] in ratio \[k : 1.\]
By section-formula,
\[(x, y) = \left(\frac{m_1x_2 + m_2x_1}{m_1 + m_2}, \frac{m_1y_2 + m_2y_1}{m_1 + m_2}\right)\]
Substituting values we get:
⇒ \[(7, y) = \left(\frac{k \times 10 + 1 \times 2}{k + 1}, \frac{k \times 12 + 1 \times 4}{k + 1}\right)\]
⇒ \[(7, y) = \left(\frac{10k + 2}{k + 1}, \frac{12k + 4}{k + 1}\right)\]
⇒ \[7 = \frac{10k + 2}{k + 1}\]
⇒ \[7(k + 1) = 10k + 2\]
⇒ \[7k + 7 = 10k + 2\]
⇒ \[10k - 7k = 7 - 2\]
⇒ \[3k = 5\]
⇒ \[k = \frac{5}{3}\]
Substituting value of \[k\] in \[k : 1\], we get:
⇒ \[\frac{5}{3} : 1\]
⇒ \[5 : 3\]
