English

The radius of the innermost electron orbit of a hydrogen atom is 5.3 × 10–11m. The radius of the n = 3 orbit is ______.

Advertisements
Advertisements

Question

The radius of the innermost electron orbit of a hydrogen atom is 5.3 × 10–11m. The radius of the n = 3 orbit is ______.

Options

  • 1.01 × 10–11m

  • 1.59 × 10–10m

  • 2.12 × 10–10m

  • 4.77 × 10–10m

MCQ
Fill in the Blanks
Advertisements

Solution

The radius of the innermost electron orbit of a hydrogen atom is 5.3 × 10–11m. The radius of the n = 3 orbit is `underline(bb(4.77 xx 10^-10 m))`.

Explanation:

The radius of an atom whose principal quantum number is n is given by r = n2r0

Where r0 = radius of innermost electron orbit for hydrogen atom and r0 = 5.3 × 10–11m

For the second excited state, n = 3

∴ r = 32 × r0

= 9 × 5.3 × 10–11

r = 4.77 × 10–10m.

shaalaa.com
  Is there an error in this question or solution?
2022-2023 (March) Sample

RELATED QUESTIONS

In accordance with the Bohr’s model, find the quantum number that characterises the earth’s revolution around the sun in an orbit of radius 1.5 × 1011 m with orbital speed 3 × 104 m/s. (Mass of earth = 6.0 × 1024 kg)


The difference in the frequencies of series limit of Lyman series and Balmer series is equal to the frequency of the first line of the Lyman series. Explain.


Find the wavelength of the radiation emitted by hydrogen in the transitions (a) n = 3 to n= 2, (b) n = 5 to n = 4 and (c) n = 10 to n = 9.


The light emitted in the transition n = 3 to n = 2 in hydrogen is called Hα light. Find the maximum work function a metal can have so that Hα light can emit photoelectrons from it.


The energy of an electron in an excited hydrogen atom is - 3.4 eV. Calculate the angular momentum of the electron according to Bohr's theory. (h = 6.626 × 10-34 Js)


Derive an expression for the frequency of radiation emitted when a hydrogen atom de-excites from level n to level (n – 1). Also show that for large values of n, this frequency equals to classical frequency of revolution of an electron.


What is the energy of an electron in stationary state corresponding to n = 2?


Energy and radius of first Bohr orbit of He+ and Li2+ are:

[Given RH = −2.18 × 10−18 J, a0 = 52.9 pm]


For the reaction \[\ce{2NO2 (g) ⇌ N2O4(g)}\], when ΔS = −176.0 JK−1 and ΔH = −57.8 kj mol−1, the magnitude of ΔG at 298 K for the reaction is ______ kJ mol−1. (Nearest integer)


The radius of hydrogen atom in the ground state is 0.53 Å. The radius of Li2+ ion (atomic number = 3) in a similar state is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×