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Question
The radius of the innermost electron orbit of a hydrogen atom is 5.3 × 10–11m. The radius of the n = 3 orbit is ______.
Options
1.01 × 10–11m
1.59 × 10–10m
2.12 × 10–10m
4.77 × 10–10m
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Solution
The radius of the innermost electron orbit of a hydrogen atom is 5.3 × 10–11m. The radius of the n = 3 orbit is `underline(bb(4.77 xx 10^-10 m))`.
Explanation:
The radius of an atom whose principal quantum number is n is given by r = n2r0
Where r0 = radius of innermost electron orbit for hydrogen atom and r0 = 5.3 × 10–11m
For the second excited state, n = 3
∴ r = 32 × r0
= 9 × 5.3 × 10–11
r = 4.77 × 10–10m.
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