Advertisements
Advertisements
Question
The radius of a circular wheel is 42 cm. Find the distance travelled by it in :
(i) 1 revolution ;
(ii) 50 revolutions ;
(iii) 200 revolutions ;
Advertisements
Solution
(i)
Radius of wheel, r = 42 cm
Circumference i.e. distance travelled in 1 revolution = 2πr = 2 x 22/7 x 42 = 264 cm
(ii)
Distance travelled in 50 revolutions = 264 x 50 = 13200 cm = 132 m
(iii)
Distance travelled in 200 revolutions = 264 x 200 = 52800 cm = 528 m
Hence (i) 264 cm (ii) 132 m (iii) 528 m
APPEARS IN
RELATED QUESTIONS
A room 4.9 m long and 3.5 m board is covered with carpet, leaving an uncovered margin of 25 cm all around the room. If the breadth of the carpet is 80 cm, find its cost at ₹ 80 per metre.
In the following figure, ABCD is a rectangle, having AB = 20 cm and BC = 14 cm. Two sectors of 180° have been cut off. Calculate:
the area of the shaded region.

From a thin metallic piece, in the shape of a trapezium ABCD, in which AB || CD and ∠BCD = 90°, a quarter circle BEFC is removed (in the following figure). Given AB = BC = 3.5 cm and DE = 2 cm, calculate the area of the remaining piece of the metal sheet.
If a wire is bent into the shape of a square, then the area of the square is 81 cm2. When wire is bent into a semi-circular shape, then the area of the semi-circle will be ______.
The radius of a wheel is 0.25 m. The number of revolutions it will make to travel a distance of 11 km will be
If the area of a sector of a circle bounded by an arc of length 5π cm is equal to 20π cm2, then the radius of the circle
The perimeter of a certain sector of a circle of radius 6.5 cm is 31 cm. Find the area of the sector.
The length of the minute hand of a clock is 21 cm. The area swept by the minute hand in 10 minutes is ______.
Find the area of a ring-shaped region enclosed between two concentric circles of radii 20 cm and 15 cm.
What is the diameter of a circle whose area is equal to the sum of the areas of two circles of radii 40cm and 9cm?
