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The radii of the circular ends of a solid frustum of a cone are 33 cm and 27 cm and its slant height is 10 cm. Find its total surface area. [Use π = 3.14.]

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Question

The radii of the circular ends of a solid frustum of a cone are 33 cm and 27 cm and its slant height is 10 cm. Find its total surface area. [Use π = 3.14.]

Sum
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Solution

Greater radius = R = 33 cm

Smaller radius = r = 27 cm

Slant height = l = 10 cm

Surface area of the frustum

= πR2 + πr2 + πl (R + r)

= π[R2 + r2 + l (R + r)]

= [332 + 272 + 10(33 + 27)]π

= [1089 + 729 + 10(60)]π

= 2418 × 3.14

= 7592.52 cm2

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Chapter 17: Volumes and Surface Areas of Solids - EXERCISE 17С [Page 823]

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 17 Volumes and Surface Areas of Solids
EXERCISE 17С | Q 13. | Page 823
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