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Question
The radii of the bases of two solid right circular cones of same height are r1 and r2 respectively. The cones are melted and recast into a solid sphere of radius R. Find the height of each cone in terms r1, r2 and R.
Sum
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Solution
Let the height of the solid cones be 'h'
Volume of solid circular cones
`V_1 = 1/3pir_1^2h`
`V_2 = 1/3pir_2^2h`
Volume of sphere
= `4/3piR^3`
Volume of sphere = Volume of cone 1 + volume of cone 2
`4/3piR^3 = 1/3pir_1^2h + 1/3pir_2^2h`
`=> 4R^3 = r_1^2h + r_2^2h`
`=> h(r_1^2 + r_2^2) = (4R)^3`
`=> h = (4R^3)/((r_1^2 + r_2^2)`
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