Advertisements
Advertisements
Question
The product of two consecutive integers is 56. Find the integers.
Advertisements
Solution
Let the two consecutive integers be x and x + 1.
From the given information,
x(x + 1) = 56
x2 + x – 56 = 0
(x + 8)(x – 7) = 0
x = – 8 or 7
Thus, the required integers are – 8 and –7; 7 and 8.
RELATED QUESTIONS
The sum of the squares of two positive integers is 208. If the square of the large number is 18 times the smaller. Find the numbers.
The sum of a number and its reciprocal is 4.25. Find the number.
Divide 15 into two parts such that the sum of their reciprocals is `3/10`.
Find two consecutive positive odd numbers, the sum of whose squares is 74.
Three positive numbers are in the ratio `1/2 : 1/3 : 1/4`. Find the numbers if the sum of their squares is 244.
Three consecutive natural numbers are such that the square of the middle number exceeds the difference of the squares of the other two by 60. Assume the middle number to be x and form a quadratic equation satisfying the above statement. Hence; find the three numbers.
The product of the digits of a two digit number is 24. If its unit’s digit exceeds twice its ten’s digit by 2; find the number.
The sum S of first n even natural numbers is given by the relation S = n(n + 1). Find n, if the sum is 420.
Two integers differ by 2 and sum of their squares is 52. The integers are ______.
In a school, a class has 40 students out of which x are girls. If the product of the number of girls and number of boys in the class is 375; the number of boys in the class is ______.
