Advertisements
Advertisements
प्रश्न
The product of two consecutive integers is 56. Find the integers.
Advertisements
उत्तर
Let the two consecutive integers be x and x + 1.
From the given information,
x(x + 1) = 56
x2 + x – 56 = 0
(x + 8)(x – 7) = 0
x = – 8 or 7
Thus, the required integers are – 8 and –7; 7 and 8.
APPEARS IN
संबंधित प्रश्न
The sum of the squares of two consecutive natural numbers is 41. Find the numbers.
The sum of a number and its reciprocal is 4.25. Find the number.
Two natural numbers differ by 3. Find the numbers, if the sum of their reciprocals is `7/10`.
Divide 15 into two parts such that the sum of their reciprocals is `3/10`.
The denominator of a positive fraction is one more than twice the numerator. If the sum of the fraction and its reciprocal is 2.9; find the fraction.
The product of the digits of a two digit number is 24. If its unit’s digit exceeds twice its ten’s digit by 2; find the number.
In a two-digit number, the ten’s digit is bigger. The product of the digits is 27 and the difference between two digits is 6. Find the number.
The sum of a number and its reciprocal is 5.2. The number is ______.
The product of two whole numbers, each greater than 4, is 35; the numbers are ______.
The sum of two whole numbers is 18 and their product is 45, the numbers are ______.
