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Question
The probability of selecting a blue marble and a red marble from a bag containing red, blue and green marbles is `1/3` and `1/5` respectively. If the bag contains 14 green marbles, then find:
- number of red marbles.
- total number of marbles in the bag.
Sum
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Solution
Given:
Let r = number of red marbles, b = number of blue marbles, g = number of green marbles = 14.
P(blue) = `b/n = 1/3` and P(red) = `r/n = 1/5`, where n = total number of marbles.
Step-wise calculation:
1. From probabilities:
`b = n/3`
`r = n/5`
2. Total count:
n = r + b + g
= `n/5 + n/3 + 14`
3. Combine fractions:
`n - (n/5 + n/3) = 14`
`n/5 + n/3 = (3n + 5n)/15`
= `(8n)/15`
`(n - 8n)/15 = (7n)/15`
`(7n)/15 = 14`
4. Solve for n:
`n = 14 xx 15/7`
= 2 × 15
= 30
5. Find r:
`r = n/5`
= `30/5`
= 6
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