Advertisements
Advertisements
Question
The present value of a machine is ₹ 16800. It depreciates at 25% p.a. Its worth after 2 years is ₹ 9450
Options
True
False
Advertisements
Solution
True
Explanation;
Hint:
Present value of machine = ₹ 16800
Depreciation rate (n) = 25%
Value after 2 years = `"P"(1 - "r"/100)^"n"`
= `16800(1 - 25/100)^2`
= `16800 xx (1 - 1/4)^2`
= `16800 xx 3/4 xx 3/4`
= 9450
APPEARS IN
RELATED QUESTIONS
The difference between the S.I. and C.I. on a certain sum of money for 2 years at 4% per annum is Rs 20. Find the sum.
Kamala borrowed from Ratan a certain sum at a certain rate for two years simple interest. She lent this sum at the same rate to Hari for two years compound interest. At the end of two years she received Rs 210 as compound interest, but paid Rs 200 only as simple interest. Find the sum and the rate of interest.
A certain sum amounts to Rs. 5,292 in two years and Rs. 5,556.60 in three years, interest being compounded annually. Find: the original sum.
Mohit invests Rs. 8,000 for 3 years at a certain rate of interest, compounded annually. At the end of one year it amounts to Rs. 9,440. Calculate:
- the rate of interest per annum.
- the amount at the end of the second year.
- the interest accrued in the third year.
A man borrows Rs.10,000 at 10% compound interest compounded yearly. At the end of each year, he pays back 20% of the amount for that year. How much money is left unpaid just after the second year ?
The difference between the C.I and S.I for 2 years for a principal of ₹ 5000 at the rate of interest 8% p.a is ___________
The time taken for ₹ 1000 to become ₹ 1331 at 20% p.a, compounded annually is 3 years
Find the compound interest for `2 1/2` years on ₹ 4000 at 10% p.a, if the interest is compounded yearly
The time taken for ₹ 4400 to become ₹ 4851 at 10%, compounded half yearly is _______
Find the difference between Compound Interest and Simple Interest on Rs 45,000 at 12% per annum for 5 years.
