Advertisements
Advertisements
प्रश्न
The present value of a machine is ₹ 16800. It depreciates at 25% p.a. Its worth after 2 years is ₹ 9450
विकल्प
True
False
Advertisements
उत्तर
True
Explanation;
Hint:
Present value of machine = ₹ 16800
Depreciation rate (n) = 25%
Value after 2 years = `"P"(1 - "r"/100)^"n"`
= `16800(1 - 25/100)^2`
= `16800 xx (1 - 1/4)^2`
= `16800 xx 3/4 xx 3/4`
= 9450
APPEARS IN
संबंधित प्रश्न
Rachana borrowed a certain sum at the rate of 15% per annum. If she paid at the end of two years Rs 1290 as interest compounded annually, find the sum she borrowed.
The difference in simple interest and compound interest on a certain sum of money at \[6\frac{2}{3} %\] per annum for 3 years is Rs 46. Determine the sum.
During every financial year, the value of a machine depreciates by 12%. Find the original cost of a machine which depreciates by Rs. 2,640 during the second financial year of its purchase.
Find the sum on which the difference between the simple interest and compound interest at the rate of 8% per annum compounded annually would be Rs. 64 in 2 years.
A sum of Rs. 13,500 is invested at 16% per annum compound interest for 5years. Calculate :
(i) the interest for the first year.
(ii) the amount at the end of first year.
(iii) the interest for the second year, correct to the nearest rupee.
Saurabh invests Rs. 48,000 for 7 years at 10% per annum compound interest. Calculate:
(i) the interest for the first year.
(ii) the amount at the end of second year.
(iii) the interest for the third year.
Mohan borrowed Rs. 16,000 for 3 years at 5% per annum compound interest. Calculate the amount that Mohan will pay at the end of 3 years.
Find the compound interest on ₹ 3200 at 2.5% p.a for 2 years, compounded annually
A principal becomes ₹ 2028 in 2 years at 4% p.a compound interest. Find the principal
The time taken for ₹ 4400 to become ₹ 4851 at 10%, compounded half yearly is _______
