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The present population of a town is 20000, it increases 2% every year. The population of the town after 2 years will be ______. - Mathematics

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Question

The present population of a town is 20000, it increases 2% every year. The population of the town after 2 years will be ______.

Options

  • 20808

  • 20804

  • 20800

  • 20400

MCQ
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Solution

The present population of a town is 20000, it increases 2% every year. The population of the town after 2 years will be 20808.

Explanation:

The present population of the town is 20,000 and it increases by 2% every year.

To find the population after 2 years, we use the compound growth formula:

`P = P_0(1 + r/100)^n`

Where:

  • P0 = 20000 present population
  • r = 2% rate of increase
  • n = 2 years

Calculating:

`P = 20000 xx (1 + 2/100)^2`

P = 20000 × (1.02)2

P = 20000 × 1.0404

P = 20808

So, the population of the town after 2 years will be 20,808.

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Chapter 2: Compound Interest - Exercise 2D [Page 53]

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Nootan Mathematics [English] Class 9 ICSE
Chapter 2 Compound Interest
Exercise 2D | Q 2. | Page 53
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