Question

The population of a town increases by 10% annually. If the present population is 60000, what will be its  population after 2 years?

Answer 1

Present population = 60000
It increases by 10 % annually.
∴ Increase in the population in the first year = 10 % of 60000 \[= \frac{10}{100} \times 60000\]
\[ = 6000\]
∴ Population after 1 year = 60000 + 6000 = 66000
Increase in the population in the second year, 10 % of 66000\[ = \frac{10}{100} \times 66000\]
\[ = 6600\]
Thus, population after 2 years = 66000 + 6600 = 72600