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The population of a town increases 10% in the first year and decreases 12% in the second year. If its present population is 118000, find its population after 2 years. - Mathematics

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Question

The population of a town increases 10% in the first year and decreases 12% in the second year. If its present population is 118000, find its population after 2 years.

Sum
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Solution

Given:

  • The population increases 10% in the first year.
  • The population decreases 12% in the second year.
  • Present population = 118,000.

Step-wise calculation:

1. Calculate population after the first year:

`P_1 = 118000 xx (1 + 10/100)`

P1 = 118000 × 1.10

P1 = 129800

2. Calculate population after the second year 12% decrease on P1:

`P_2 = 129800 xx (1 - 12/100)`

P2 = 129800 × 0.88

P2 = 114224

The population of the town after 2 years will be 114,224.

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Chapter 2: Compound Interest - Exercise 2C [Page 53]

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Nootan Mathematics [English] Class 9 ICSE
Chapter 2 Compound Interest
Exercise 2C | Q 8. | Page 53
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