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Question
The point P on x-axis equidistant from the points A(–1, 0) and B(5, 0) is ______.
Options
(2, 0)
(0, 2)
(3, 0)
(2, 2)
MCQ
Fill in the Blanks
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Solution
The point P on x-axis equidistant from the points A(–1, 0) and B(5, 0) is (2, 0).
Explanation:
Let the position of the point P on x-axis be (x, 0), then
PA2 = PB2
⇒ (x + 1)2 + (0)2 = (5 – x)2 + (0)2
⇒ x2 + 2x + 1 = 25 + x2 – 10x
⇒ 2x + 10x = 25 – 1
⇒ 12x = 24
⇒ x = 2
Hence, the point P (x, 0) is (2, 0).
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