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Question
The perpendicular BD drawn from the vertex of a right triangle ABC.
Assertion (A): Triangles ABD and BCD are similar to each other.
Reason (R): Triangles, which are similar to the same triangle, are similar to each other.

Options
A is true, R is false.
A is false, R is true.
Both A and R are true and R is the correct reason for A.
Both A and R are true and R is the incorrect reason for A .
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Solution
Both A and R are true and R is the correct reason for A.
Explanation:
In Δ ABC and Δ ABD,
⇒ ∠ABC = ∠ADB (Both are 90°)
⇒ ∠BAC = ∠BAD (Common angle)
∴ Δ ABC ∼ Δ ADB (By AA postulate) .......... (1)
Similarly, in Δ ABC and Δ BDC,
⇒ ∠ABC = ∠BDC (Both are 90°)
⇒ ∠BCA = ∠BCD (Common angles)
∴ Δ ABC ∼ Δ BDC (By AA postulate) .......... (2)
As,
Triangles, which are similar to the same triangle, are similar to each other.
From equation (1) and (2), we get:
Δ ADB ∼ Δ BDC
∴ Both A and R are true and R is correct reason for A.
