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The perpendicular BD drawn from the vertex of a right triangle ABC. Assertion (A): Triangles ABD and BCD are similar to each other. Reason (R): Triangles, which are similar to the same triangle

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Question

The perpendicular BD drawn from the vertex of a right triangle ABC.

Assertion (A): Triangles ABD and BCD are similar to each other.

Reason (R): Triangles, which are similar to the same triangle, are similar to each other.

The image displays a right-angled triangle ABC with a right angle at vertex B and an internal perpendicular altitude segment BD dropped to the hypotenuse AC, marked with right-angle symbols. It illustrates the geometric mean theorem, triangle similarity, and proportional side relationships within right-angled triangles.

Options

  • A is true, R is false.

  • A is false, R is true.

  • Both A and R are true and R is the correct reason for A.

  • Both A and R are true and R is the incorrect reason for A .

MCQ
Assertion and Reasoning
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Solution

Both A and R are true and R is the correct reason for A.

Explanation:

In Δ ABC and Δ ABD,

⇒ ∠ABC = ∠ADB (Both are 90°)

⇒ ∠BAC = ∠BAD (Common angle)

∴ Δ ABC ∼ Δ ADB (By AA postulate) .......... (1)

Similarly, in Δ ABC and Δ BDC,

⇒ ∠ABC = ∠BDC (Both are 90°)

⇒ ∠BCA = ∠BCD (Common angles)

∴ Δ ABC ∼ Δ BDC (By AA postulate) .......... (2)

As,

Triangles, which are similar to the same triangle, are similar to each other.

From equation (1) and (2), we get:

Δ ADB ∼ Δ BDC

∴ Both A and R are true and R is correct reason for A.

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Chapter 15: Similarity (With Applications to Maps and Models) - TEST YOURSELF [Page 232]

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Selina Concise Mathematics [English] Class 10 ICSE
Chapter 15 Similarity (With Applications to Maps and Models)
TEST YOURSELF | Q 1. (h) | Page 232
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