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Question
The perimeters of two squares are 40 and 96 metres respectively. Find the perimeter of another square equal in area to the sum of the first two squares.
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Solution
Given: Perimeter of one square = 40 m
Let length of square = a1
Then 4a1 = 40 m
⇒ a1 = 10 m
Area of square = a1 × a1
= 10 × 10
= 100 m2
Perimeter of second square = 96 m
Let length of square = a2
Then 4a2 = 96 m
⇒ a2 = 24 m
Area of square = a2 × a2
= 24 × 24
= 576 m2
Because, perimeter of another square equal in area to the sum of the first two squares.
Hence, area of another square = 100 + 576 = 676 m
Area of square = a3 × a3
676 = (a3)2
⇒ a3 = 26 m
Hence, perimeter = 4a3
= 4 × 26
= 104 m
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