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Question
The perimeter of a right-angled triangle is five times the length of the shortest side. The numerical value of the area of the triangle is 15 times the numerical value of the length of the shortest side. Find the lengths of the three sides of the triangle.
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Solution
Let the shortest side of the right-angled triangle be x.
Let the other side be y and the hypotenuse be z.
Given:
Perimeter = 5 × shortest side
x + y + z = 5x
⇒ y + z = 4x ...(1)
Area = 15 × shortest side
Area of a right-angled triangle:
`1/2 xx x xx y = 15x`
Cancel x (x ≠ 0):
`1/2 y = 15`
⇒ y = 30
z2 = x2 + y2
= x2 + 302
= x2 + 900
From (1):
z = 4x − y = 4x − 30
(4x − 30)2 = x2 + 900
16x2 − 240x + 900 = x2 + 900
15x2 − 240x = 0
15x(x − 16) = 0
x = 16
Find the remaining sides:
y = 30
`z = sqrt(16^2 + 30^2)`
`= sqrt(256 + 900)`
`= sqrt1156`
= 34
Lengths of the sides are:
Shortest side = 16
Other side = 30
Hypotenuse = 34
