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The perimeter of a right-angled triangle is five times the length of the shortest side. - Mathematics

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Question

The perimeter of a right-angled triangle is five times the length of the shortest side. The numerical value of the area of the triangle is 15 times the numerical value of the length of the shortest side. Find the lengths of the three sides of the triangle.

Sum
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Solution

Let the shortest side of the right-angled triangle be x.

Let the other side be y and the hypotenuse be z.

Given:

Perimeter = 5 × shortest side

x + y + z = 5x

⇒ y + z = 4x     ...(1)

Area = 15 × shortest side

Area of a right-angled triangle:

`1/2 xx x xx y = 15x`

Cancel x (x ≠ 0):

`1/2 y = 15`

⇒ y = 30

z2 = x2 + y2

= x2 + 302

= x2 + 900

From (1):

z = 4x − y = 4x − 30

(4x − 30)2 = x2 + 900

16x2 − 240x + 900 = x2 + 900

15x2 − 240x = 0

15x(x − 16) = 0

x = 16

Find the remaining sides:

y = 30

`z = sqrt(16^2 + 30^2)`

`= sqrt(256 + 900)`

`= sqrt1156`

= 34

Lengths of the sides are:

Shortest side = 16

Other side = 30

Hypotenuse = 34

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Chapter 5: Quadratic equations - Chapter Test [Page 96]

APPEARS IN

Nootan Mathematics [English] Class 10 ICSE
Chapter 5 Quadratic equations
Chapter Test | Q 9. | Page 96
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