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The perimeter of a right-angled triangle is five times the length of the shortest side. - Mathematics

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प्रश्न

The perimeter of a right-angled triangle is five times the length of the shortest side. The numerical value of the area of the triangle is 15 times the numerical value of the length of the shortest side. Find the lengths of the three sides of the triangle.

योग
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उत्तर

Let the shortest side of the right-angled triangle be x.

Let the other side be y and the hypotenuse be z.

Given:

Perimeter = 5 × shortest side

x + y + z = 5x

⇒ y + z = 4x     ...(1)

Area = 15 × shortest side

Area of a right-angled triangle:

`1/2 xx x xx y = 15x`

Cancel x (x ≠ 0):

`1/2 y = 15`

⇒ y = 30

z2 = x2 + y2

= x2 + 302

= x2 + 900

From (1):

z = 4x − y = 4x − 30

(4x − 30)2 = x2 + 900

16x2 − 240x + 900 = x2 + 900

15x2 − 240x = 0

15x(x − 16) = 0

x = 16

Find the remaining sides:

y = 30

`z = sqrt(16^2 + 30^2)`

`= sqrt(256 + 900)`

`= sqrt1156`

= 34

Lengths of the sides are:

Shortest side = 16

Other side = 30

Hypotenuse = 34

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अध्याय 5: Quadratic equations - Chapter Test [पृष्ठ ९६]

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नूतन Mathematics [English] Class 10 ICSE
अध्याय 5 Quadratic equations
Chapter Test | Q 9. | पृष्ठ ९६
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