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The numbers 6, 8, 10, 12, 13 and x are arranged in an ascending order. If the mean of the observations is equal to the median, find the value of x.

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Question

The numbers 6, 8, 10, 12, 13 and x are arranged in an ascending order. If the mean of the observations is equal to the median, find the value of x.

Sum
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Solution

The numbers are 6, 8, 10, 12, 13 and x

Mean = `(6 + 8 + 10 + 12 + 13 + x)/(6)`

Mean = `(49 + x)/(6)`   ...(1)

For Median

n = 6  ...(Even)

Median = `((n/2)^(th) term + (n/2 + 1)^(th) term)/(2)`

∴ Median = `(3^(rd)  term + 4^(th)  term)/(2)`

= `(10 + 12)/(2)`

= `(22)/(2)`

= 11       ...(2)

From (1) and (2) (From question)

Median = Mean

∴ `11 = (49 + x)/(6)`

`=>` x = 66 – 49

`=>` x = 17

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Chapter 24: Measure of Central Tendency (Mean, Median, Quartiles and Mode) - Exercise 24 (E) [Page 377]

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Selina Concise Mathematics [English] Class 10 ICSE
Chapter 24 Measure of Central Tendency (Mean, Median, Quartiles and Mode)
Exercise 24 (E) | Q 17. | Page 377
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