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Question
The molar solubility of calcium oxalate, CaC2O4 at 25°C is 4.8 × 10−5 mol/dm3. The value of Ksp is ___________.
Options
2.3 × 10−9
2.3 × 10−10
4.4 × 10−9
4.4 × 10−10
MCQ
Fill in the Blanks
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Solution
The molar solubility of calcium oxalate, CaC2O4 at 25°C is 4.8 × 10−5 mol/dm3. The value of Ksp is 2.3 × 10−9.
Explanation:
\[\ce{CaC2O4_{(s)} ⇌ \underset{S}{Ca^{2+}_{( aq)}} + \underset{S}{C2O^{2-}_{4(aq)}}}\]
Ksp = \[\ce{[Ca^{2+}] [C2O^{2-}_4]}\]
= S × S
= 4.8 × 10−5 × 4.8 × 10−5
= 23.04 × 10−10
= 2.3 × 10−9
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Concept of Solubility Equilibria of Sparingly Soluble Salts - Solubility Product Constant
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