Question

The molar solubility of calcium oxalate, CaC₂O₄ at 25°C is 4.8 × 10⁻⁵ mol/dm³. The value of K_sp is ___________.

पर्याय

• 2.3 × 10⁻⁹

• 2.3 × 10⁻¹⁰

• 4.4 × 10⁻⁹

• 4.4 × 10⁻¹⁰

Answer 1

The molar solubility of calcium oxalate, CaC₂O₄ at 25°C is 4.8 × 10⁻⁵ mol/dm³. The value of K_sp is 2.3 × 10⁻⁹.

Explanation:

\[\ce{CaC2O4_{(s)} ⇌ \underset{S}{Ca^{2+}_{( aq)}} + \underset{S}{C2O^{2-}_{4(aq)}}}\]

K_sp = \[\ce{[Ca^{2+}] [C2O^{2-}_4]}\]

= S × S

= 4.8 × 10⁻⁵ × 4.8 × 10⁻⁵

= 23.04 × 10⁻¹⁰

= 2.3 × 10⁻⁹