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Question
The molar conductivity of a 0.5 mol dm−3 solution of AgNO3 with electrolytic conductivity of 5.76 × 10−3 S cm−1 at 298 K is ____________.
Options
2.88 S cm2 mol−1
11.52 S cm2 mol−1
0.086 S cm2 mol−1
28.8 S cm2 mol−1
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Solution
The molar conductivity of a 0.5 mol dm−3 solution of AgNO3 with electrolytic conductivity of 5.76 × 10−3 S cm−1 at 298 K is 11.52 S cm2 mol−1.
Explanation:
Λ = `"κ"/"M" xx 10^-3 "mol"^-1 "m"^3`
= `(5.76 xx 10^-3 xx "S cm"^-1 xx 10^-3)/0.5` mol−1 m3
= `(5.76 xx 10^-3 xx 10^-3 xx 10^6)/0.5` S cm−1 mol−1 cm3
= 11.52 S cm2 mol−1
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