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Question
The minimum energy required to launch a satellite of mass m from the surface of earth of mass M and radius R in a circular orbit at an altitude of 2R from the surface of the earth is ______.
Options
`(5 GmM)/(6 R)`
`(2 GmM)/(3 R)`
`(GmM)/(2 R)`
`(GmM)/(3 R)`
MCQ
Fill in the Blanks
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Solution
The minimum energy required to launch a satellite of mass m from the surface of earth of mass M and radius R in a circular orbit at an altitude of 2R from the surface of the earth is `bbunderline((5 GmM)/(6 R))`.
Explanation:

Let us apply the energy conservation law, we get.
U + K = U + K
⇒ `-(GMm)/R + K_i = - (GmM)/(3 R) + 1/2 mv^2`
⇒ `- (GMm)/R + K_i = - (GmM)/(3 R) + 1/2 xx m xx (GM)/(3 R)`
⇒ Ki = `-1/6 (GMm)/R + (GMm)/R`
= `5/6 (GMm)/R`
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