Advertisements
Advertisements
Question
The middle term in the expansion of `(x + 1/x)^10` is
Options
10C4 `(1/x)`
10C5
10C6
10C7 x2
Advertisements
Solution
10C5
APPEARS IN
RELATED QUESTIONS
Evaluate the following using binomial theorem:
(101)4
Show that the middle term in the expansion of is (1 + x)2n is `(1*3*5...(2n - 1)2^nx^n)/(n!)`
Expand `(2x^2 - 3/x)^3`
Compute 97
Using binomial theorem, indicate which of the following two number is larger: `(1.01)^(1000000)`, 10
Find the coefficient of x2 and the coefficient of x6 in `(x^2 -1/x^3)^6`
Find the coefficient of x4 in the expansion `(1 + x^3)^50 (x^2 + 1/x)^5`
Find the constant term of `(2x^3 - 1/(3x^2))^5`
If n is an odd positive integer, prove that the coefficients of the middle terms in the expansion of (x + y)n are equal
Prove that `"C"_0^2 + "C"_1^2 + "C"_2^2 + ... + "C"_"n"^2 = (2"n"!)/("n"!)^2`
