Advertisements
Advertisements
प्रश्न
The middle term in the expansion of `(x + 1/x)^10` is
पर्याय
10C4 `(1/x)`
10C5
10C6
10C7 x2
Advertisements
उत्तर
10C5
APPEARS IN
संबंधित प्रश्न
Evaluate the following using binomial theorem:
(101)4
Evaluate the following using binomial theorem:
(999)5
Expand the following by using binomial theorem.
`(x + 1/x^2)^6`
Find the 5th term in the expansion of (x – 2y)13.
Find the term independent of x in the expansion of
`(x^2 - 2/(3x))^9`
The constant term in the expansion of `(x + 2/x)^6` is
If n is an odd positive integer, prove that the coefficients of the middle terms in the expansion of (x + y)n are equal
If the binomial coefficients of three consecutive terms in the expansion of (a + x)n are in the ratio 1 : 7 : 42, then find n
Prove that `"C"_0^2 + "C"_1^2 + "C"_2^2 + ... + "C"_"n"^2 = (2"n"!)/("n"!)^2`
Choose the correct alternative:
The remainder when 3815 is divided by 13 is
